What is the longest pipe which can be maneuvered around a corner? - pipe calculation potential energy
What is the longest pipe, which are maneuvered into a corner to enable them to achieve a range of between 9 feet wide and 5 meters wide corridor? Let us assume that the tube should be during the maneuvers in the horizontal position, and ignore a the diameter of the tube in the calculation.
To resolve this problem, we must find the fixed point of the following function of t = angle? Answer?
The breakpoint occurs when tan (t) =? Answer?
Thus, the maximum length of the tube is formed? Answer?
Monday, February 8, 2010
Pipe Calculation Potential Energy What Is The Longest Pipe Which Can Be Maneuvered Around A Corner?
2 comments:
Interesting question.
I let the parameter θ =, and the acute angle between the tube and the outer wall of the 5-foot corridor. Of course, the longer tube will be playing both corner walls and the inside corner.
At this point 9secθ Prize "of the length of the pipe to the 5-foot corridor is 5cscθ and length of the 9-foot runner.
Total length 5cscθ + 9secθ
The maximum value of R is the first derivative with respect to θ and equal to zero.
L = 5cscθ + 9secθ
L '= 9secθtanθ + 5cscθctnθ = 0
9secθtanθ = 5cscθctnθ
Using trigonometric identities, this equation reduces to
³, where θ = 5 / 9 (Note: the width) of the transition in this speech
θ = 39.42 °
Just plug it into the original equation to find the maximum length of the tube
L = 19.52 '
(9 +5) * sqrt (2)
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